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(C) $1$. Calculate the number of incident photons per second $(N_i)$: Intensity $I = 16 \, mW/m^2 = 16 	imes 10^{-3} \, W/m^2$. Area $A = 1 	imes 10

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$10^{11}$ and $5 \, eV$

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(C) $1$. Calculate the number of incident photons per second $(N_i)$: Intensity $I = 16 \, mW/m^2 = 16 	imes 10^{-3} \, W/m^2$. Area $A = 1 	imes 10^{-4} \, m^2$. Energy of one photon $E = 10 \, eV = 10 	imes 1.6 	imes 10^{-19} \, J = 1.6 	imes 10^{-18} \, J$. Total power incident $P = I 	imes A = 16 	imes 10^{-3} 	imes 10^{-4} = 16 	imes 10^{-7} \, W$. $N_i = P / E = (16 	imes 10^{-7}) / (1.6 	imes 10^{-18}) = 10^{12} \, 	ext{photons/second}$. $2$. Calculate the number of emitted photoelectrons per second $(N_e)$: $N_e = 10\% 	ext{ of } N_i = 0.1 	imes 10^{12} = 10^{11} \, 	ext{electrons/second}$. $3$. Calculate the maximum kinetic energy $(K_{\max})$: Using Einstein's photoelectric equation: $K_{\max} = E - \phi = 10 \, eV - 5 \, eV = 5 \, eV$.

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