A metal rod of 1 ; m length is dropped vertic | vedclass

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(A) When a rod of length $L$ is dropped vertically on a hard floor,it acts like a rod with both ends free (or a rod fixed at the point of impact,but t

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$2400$

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(A) When a rod of length $L$ is dropped vertically on a hard floor,it acts like a rod with both ends free (or a rod fixed at the point of impact,but the fundamental mode of vibration for a rod struck in this manner corresponds to the fundamental frequency of a rod free at both ends).The fundamental frequency $f$ for a rod of length $L$ is given by $f = \frac{v}{2L}$,where $v$ is the speed of sound in the rod.Given: $L = 1 \; m$ and $f = 1.2 \; kHz = 1200 \; Hz$.Rearranging the formula to solve for $v$: $v = f 	imes 2L$.Substituting the values: $v = 1200 \; Hz 	imes 2 	imes 1 \; m$.$v = 2400 \; m/s$.

$A$ metal rod of $1 \; m$ length is dropped vertically onto a hard metal floor. Using an oscilloscope,it is determined that the impact produces a longitudinal wave of $1.2 \; kHz$ frequency. The speed of sound in the metal rod is: (in $; m/s$)

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