A metallic block carrying current I is subjec | vedclass

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Question

(A) Since the block is metallic,the charge carriers are electrons. For a current $I$ along the positive $x$-axis,the electrons move along the negative

Vedclass · Accepted Answer

$evB\,\hat{k}$,$ABCD$

Vedclass · Answer

(A) Since the block is metallic,the charge carriers are electrons. For a current $I$ along the positive $x$-axis,the electrons move along the negative $x$-axis,i.e.,$\overrightarrow{v} = -v\hat{i}$.The magnetic field is along the $y$-axis,i.e.,$\overrightarrow{B} = B\hat{j}$.The Lorentz force is given by $\overrightarrow{F} = q(\overrightarrow{v} 	imes \overrightarrow{B})$.Substituting the values,$\overrightarrow{F} = (-e)(-v\hat{i} 	imes B\hat{j}) = evB(\hat{i} 	imes \hat{j}) = evB\hat{k}$.Since the force on the electrons is in the positive $z$-direction,they accumulate on the face $ABCD$ (as per the coordinate system shown in the figure). The accumulation of negative charges on face $ABCD$ results in the lowering of its potential.

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