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(D) The magnetic field produced by the long wire is directed into the plane of the frame. According to Fleming's Right-Hand Rule,the induced emf in si

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$0.5\, A, CW$

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(D) The magnetic field produced by the long wire is directed into the plane of the frame. According to Fleming's Right-Hand Rule,the induced emf in side $AD$ (closer to the wire) will be directed from $D$ to $A$,and in side $BC$ (farther from the wire) it will be directed from $C$ to $B$.Since the magnetic field is stronger near the wire,the emf in $AD$ $(5\,V)$ is greater than the emf in $BC$ $(2\,V)$.These two emfs act in opposition within the loop. The net emf in the loop is $\varepsilon_{net} = \varepsilon_{AD} - \varepsilon_{BC} = 5\,V - 2\,V = 3\,V$.The direction of this net emf is determined by the larger emf,which is along $D \rightarrow A \rightarrow B \rightarrow C \rightarrow D$ (Clockwise).The induced current $I$ is given by $I = \frac{\varepsilon_{net}}{R} = \frac{3\,V}{6\,\Omega} = 0.5\,A$.Since the net emf drives the current in a clockwise direction,the induced current is $0.5\,A$ in the $CW$ direction.

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