A millivoltmeter of 25 , mV range is to be co | vedclass

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(A) To convert a millivoltmeter into an ammeter,a shunt resistance $R_s$ is connected in parallel with the meter.Let $V_m$ be the full-scale voltage o

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$0.001$

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(A) To convert a millivoltmeter into an ammeter,a shunt resistance $R_s$ is connected in parallel with the meter.Let $V_m$ be the full-scale voltage of the millivoltmeter and $I$ be the desired full-scale current of the ammeter.The voltage across the millivoltmeter is $V_m = 25 	imes 10^{-3} \, V$.The current through the shunt is approximately equal to the total current $I = 25 \, A$ because the resistance of the millivoltmeter is very high compared to the shunt.The voltage across the shunt must equal the voltage across the millivoltmeter:$V_m = I 	imes R_s$$25 	imes 10^{-3} = 25 	imes R_s$$R_s = \frac{25 	imes 10^{-3}}{25} = 10^{-3} \, \Omega = 0.001 \, \Omega$.

$A$ millivoltmeter of $25 \, mV$ range is to be converted into an ammeter of $25 \, A$ range. The value (in $\Omega$) of the necessary shunt will be:

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