$A$ mineral consists of a cubic close-packed structure formed by $O^{2-}$ ions,where half the octahedral voids are occupied by $Al^{3+}$ and one-eighth of the tetrahedral voids are occupied by $Mn^{2+}$. The chemical formula of the mineral is
- A$Mn_{3}Al_{2}O_{6}$
- B$MnAl_{2}O_{4}$
- C$MnAl_{4}O_{7}$
- D$Mn_{2}Al_{2}O_{5}$
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Similar Questions
$A$ solid is made of two elements $X$ and $Y$. Atoms of $X$ are in $FCC$ arrangement and $Y$ atoms occupy all tetrahedral sites. What is the possible formula of the compound?
In a face-centred cubic arrangement of $A$ and $B$ atoms,$A$ atoms are at the corners of the unit cell and $B$ atoms are at the face centres. If one of the $A$ atoms is missing from one corner of the unit cell,what is the simplest formula of the compound?
In a cubic close-packed $(ccp)$ structure,if there are $N$ spheres,what is the number of octahedral voids?
Easy
View SolutionIn a cubic close packed structure,the fractional contributions of an atom at the corner and at the face in the unit cell are,respectively:
MediumKVPY 2014
View SolutionIf the anion $(A)$ forms a hexagonal closest packing and the cation $(C)$ occupies only $2/3$ of the octahedral voids in it,then the general formula of the compound is :-
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