A mixture of hydrogen and oxygen contains 40 | vedclass

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(B) Let the total mass of the mixture be $100 \, g$.Mass of $H_2 = 40 \, g$,so moles of $H_2$ $(n_{H_2})$ $= \frac{40}{2} = 20 \, mol$.Mass of $O_2 =

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$2$

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(B) Let the total mass of the mixture be $100 \, g$.Mass of $H_2 = 40 \, g$,so moles of $H_2$ $(n_{H_2})$ $= \frac{40}{2} = 20 \, mol$.Mass of $O_2 = 60 \, g$,so moles of $O_2$ $(n_{O_2})$ $= \frac{60}{32} = 1.875 \, mol$.Mole fraction of $H_2$ $(x_{H_2})$ $= \frac{n_{H_2}}{n_{H_2} + n_{O_2}} = \frac{20}{20 + 1.875} = \frac{20}{21.875} \approx 0.9143$.Partial pressure of $H_2$ $(P_{H_2})$ $= x_{H_2} 	imes P_{total} = 0.9143 	imes 2.2 \, bar = 2.01146 \, bar$.The nearest integer is $2 \, bar$.

$A$ mixture of hydrogen and oxygen contains $40 \%$ hydrogen by mass when the total pressure is $2.2 \, bar$. The partial pressure of hydrogen is $bar$. (Nearest Integer)

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