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(C) The radius $(r)$ of each cylindrical pillar is half of the diameter: $r = \frac{50\, cm}{2} = 25\, cm = 0.25\, m = \frac{1}{4}\, m.$The height $(h

Vedclass · Accepted Answer

$157$

Vedclass · Answer

(C) The radius $(r)$ of each cylindrical pillar is half of the diameter: $r = \frac{50\, cm}{2} = 25\, cm = 0.25\, m = \frac{1}{4}\, m.$The height $(h)$ of each pillar is $4\, m.$The curved surface area of one cylindrical pillar is given by the formula $2\pi rh.$Curved surface area of one pillar $= 2 	imes 3.14 	imes \frac{1}{4} 	imes 4 = 6.28\, m^{2}.$The total curved surface area for $50$ such pillars $= 50 	imes 6.28\, m^{2} = 314\, m^{2}.$The cleaning rate is $50$ $paise$ per $m^{2},$ which is equal to $₹ 0.50$ per $m^{2}.$Total labour charges $= 314\, m^{2} 	imes ₹ 0.50/m^{2} = ₹ 157.$

$A$ monument has $50$ cylindrical pillars each of diameter $50\, cm$ and height $4\, m.$ What will be the labour charges for cleaning these pillars at the rate of $50$ $paise$ per $m^{2}?$ (in $Rs.$) (Use $\pi=3.14$)

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