A narrow,paraxial beam of light is converging | vedclass

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Question

(A) When a parallel-sided glass slab of thickness $t$ and refractive index $\mu$ is placed in the path of a converging beam,the light rays are refract

Vedclass · Accepted Answer

$t(1 - 1/\mu)$ away

Vedclass · Answer

(A) When a parallel-sided glass slab of thickness $t$ and refractive index $\mu$ is placed in the path of a converging beam,the light rays are refracted towards the normal upon entering the glass and away from the normal upon exiting.This causes the point of convergence to shift in the direction of the incident light.The longitudinal shift $\Delta x$ produced by a glass slab is given by the formula $\Delta x = t(1 - 1/\mu)$.Since the shift is in the direction of the incident light,the convergence point moves away from the slab (further from the original position).Therefore,the correct option is $A$.

$A$ narrow,paraxial beam of light is converging towards a point $I$ on a screen. $A$ plane parallel plate of glass of thickness $t$ and refractive index $\mu$ is introduced in the path of the beam. The convergence point is shifted by

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