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(C) Let $A$ be the event that $5$ appears on at least one die.The sample space for two dice is $36$. The outcomes where $5$ appears are: $(5, 1), (5,

Vedclass · Accepted Answer

$\frac{3}{11}$

Vedclass · Answer

(C) Let $A$ be the event that $5$ appears on at least one die.The sample space for two dice is $36$. The outcomes where $5$ appears are: $(5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6), (1, 5), (2, 5), (3, 5), (4, 5), (6, 5)$.Total number of outcomes in $A$ is $n(A) = 11$.Let $B$ be the event that the sum is $10$ or greater.We need to find the conditional probability $P(B|A) = \frac{n(A \cap B)}{n(A)}$.The outcomes in $A$ where the sum is $10$ or greater are: $(5, 5), (5, 6), (6, 5)$.Thus,$n(A \cap B) = 3$.Therefore,the required probability is $P(B|A) = \frac{3}{11}$.

$A$ pair of dice is thrown. If $5$ appears on at least one of the dice,then the probability that the sum is $10$ or greater is:

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