$A$ pair of tangents are drawn from the origin to the circle $x^2 + y^2 + 20(x + y) + 20 = 0$. The equation of the pair of tangents is

  • A
    $x^2 + y^2 + 10xy = 0$
  • B
    $x^2 + y^2 + 5xy = 0$
  • C
    $2x^2 + 2y^2 + 5xy = 0$
  • D
    $2x^2 + 2y^2 - 5xy = 0$

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$ax - y + c = 0$ is the equation of the common tangent to the parabola $y^2 = 8\sqrt{5}x$ and the circle $x^2 + y^2 = 1$. If this tangent makes an acute angle with the positive $X$-axis,then $a^2c^2 =$

Let $P(3 \cos \alpha, 2 \sin \alpha)$, $\alpha \neq 0$, be a point on the ellipse $\frac{x^2}{9} + \frac{y^2}{4} = 1$, $Q$ be a point on the circle $x^2 + y^2 - 14x - 14y + 82 = 0$, and $R$ be a point on the line $x + y = 5$ such that the centroid of the triangle $PQR$ is $(2 + \cos \alpha, 3 + \frac{2}{3} \sin \alpha)$. Then the sum of the ordinates of all possible points $R$ is:

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For the circle $C$ with the equation $x^2+y^2-16x-12y+64=0$,match the List-$I$ with the List-$II$ given below.
List-$I$List-$II$
$(i)$ The equation of the polar of $(-5, 1)$ with respect to $C$$(A)$ $y = 0$
$(ii)$ The equation of the tangent at $(8, 0)$ to $C$$(B)$ $y = 6$
$(iii)$ The equation of the normal at $(2, 6)$ to $C$$(C)$ $x + y = 7$
$(iv)$ The equation of the diameter of $C$ through $(8, 12)$$(D)$ $13x + 5y = 98$
$(E)$ $x = 8$

The correct match is:

If the tangent to the circle $x^2 + y^2 = r^2$ at the point $(a, b)$ meets the coordinate axes at the points $A$ and $B$,and $O$ is the origin,then the area of the triangle $OAB$ is

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