(B) The potential difference $V$ across the capacitor remains constant because it is connected to a constant potential source.Since $V = E \cdot d$,wh

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some extra charge from the source will flow into the capacitor.

(B) The potential difference $V$ across the capacitor remains constant because it is connected to a constant potential source.Since $V = E \cdot d$,where $d$ is the distance between the plates,and $V$ and $d$ are constant,the electric field intensity $E$ remains unchanged.As the dielectric is introduced,the capacitance $C$ increases ($C = K C_0$,where $K > 1$).Since $Q = C V$ and $V$ is constant,the charge $Q$ on the capacitor increases.Therefore,some extra charge from the source flows into the capacitor.

Class 12 Physics Electric Potential and Capacitance Effect of Dielectric Inside Capacitor

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$A$ parallel plate air-core capacitor is connected across a source of constant potential difference. When a dielectric plate is introduced between the two plates,then:

A
some charge from the capacitor will flow back into the source.
B
some extra charge from the source will flow into the capacitor.
C
the electric field intensity between the two plates does not change.
D
$B$ and $C$ both

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Electric Potential and Capacitance

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Effect of Dielectric Inside Capacitor

$A$ parallel plate capacitor is immersed in an oil of dielectric constant $K = 2$. The electric field between the plates is:

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$A$ parallel plate capacitor of capacitance $12.5 \ pF$ is charged by a battery connected between its plates to a potential difference of $12.0 \ V$. The battery is now disconnected and a dielectric slab $(\epsilon_{r}=6)$ is inserted between the plates. The change in its potential energy after inserting the dielectric slab is . . . . . . . $\times 10^{-12} \ J$.

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Two identical parallel plate capacitors of capacitance $C$ each are connected in series with a battery of emf $E$ as shown below. If one of the capacitors is now filled with a dielectric of dielectric constant $k$,then the amount of charge which will flow through the battery is (neglect internal resistance of the battery).

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$A$ parallel plate capacitor is charged to a certain potential and the charging battery is then disconnected. Now,if the plates of the capacitor are moved apart,then:

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When a dielectric material is introduced between the plates of a charged capacitor,the electric field between the plates:

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$A$ parallel plate air-core capacitor is connected across a source of constant potential difference. When a dielectric plate is introduced between the two plates,then:

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$A$ parallel plate capacitor is immersed in an oil of dielectric constant $K = 2$. The electric field between the plates is:

$A$ parallel plate capacitor is charged to a certain potential and the charging battery is then disconnected. Now,if the plates of the capacitor are moved apart,then:

When a dielectric material is introduced between the plates of a charged capacitor,the electric field between the plates:

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