(A) Since the battery remains connected,the potential difference across the plates remains constant. Therefore,$V = V_0$.The electric field is given b

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(A) Since the battery remains connected,the potential difference across the plates remains constant. Therefore,$V = V_0$.The electric field is given by $E = V/d$. Since $V$ and the separation $d$ remain unchanged,$E = E_0$.Let the initial capacitance be $C_0$. When a dielectric slab of constant $K$ is inserted,the new capacitance becomes $C = K C_0$,where $K > 1$.The charge on the capacitor is $Q = CV = (K C_0) V_0 = K Q_0$. Since $K > 1$,it follows that $Q > Q_0$.The energy stored in the capacitor is $U = (1/2) CV^2 = (1/2) (K C_0) V_0^2 = K U_0$. Since $K > 1$,it follows that $U > U_0$.Thus,the correct relation is $Q > Q_0$.

Class 12 Physics Electric Potential and Capacitance Effect of Dielectric Inside Capacitor

Medium

$A$ parallel plate capacitor is connected to a battery. The quantities charge,voltage,electric field,and energy associated with the capacitor are given by $Q_0, V_0, E_0$,and $U_0$ respectively. $A$ dielectric slab is introduced between the plates of the capacitor,but the battery remains connected. The corresponding quantities now given by $Q, V, E$,and $U$ related to the previous ones are:

A
$Q > Q_0$
B
$V > V_0$
C
$E > E_0$
D
$U < U_0$

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Class 12

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Electric Potential and Capacitance

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Effect of Dielectric Inside Capacitor

$A$ capacitor has some dielectric between its plates and the capacitor is connected to a $D.C.$ source. The battery is now disconnected and then the dielectric is removed. State whether the capacitance,the energy stored in it,electric field,charge stored,and the voltage will increase,decrease,or remain constant.

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$A$ parallel plate capacitor filled with oil of a dielectric constant $3$ between the plates has capacitance $C$. If the oil is removed,then the capacitance of the capacitor will be

EasyMHT CET 2021

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$A$ parallel plate capacitor has plate area $40 \text{ cm}^2$ and plate separation $2 \text{ mm}$. The space between the plates is filled with a dielectric medium of thickness $1 \text{ mm}$ and dielectric constant $K = 5$. The capacitance of the system is:

DifficultMHT CET 2026

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$A$ simple pendulum of mass $m$, length $l$, and charge $+q$ is suspended in the electric field produced by two conducting parallel plates as shown. The value of the deflection of the pendulum in the equilibrium position will be -

DifficultJEE MAIN 2021

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$A$ parallel plate capacitor with air between the plates has a capacitance of $12 \mu F$. If the distance between the plates is doubled and the space between the plates is filled with a substance of dielectric constant $4$,what will be the new capacitance of the capacitor (in $\mu F$)?

MediumAP EAMCET 2022

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$A$ parallel plate capacitor filled with oil of a dielectric constant $3$ between the plates has capacitance $C$. If the oil is removed,then the capacitance of the capacitor will be

$A$ parallel plate capacitor has plate area $40 \text{ cm}^2$ and plate separation $2 \text{ mm}$. The space between the plates is filled with a dielectric medium of thickness $1 \text{ mm}$ and dielectric constant $K = 5$. The capacitance of the system is:

$A$ simple pendulum of mass $m$, length $l$, and charge $+q$ is suspended in the electric field produced by two conducting parallel plates as shown. The value of the deflection of the pendulum in the equilibrium position will be -

$A$ parallel plate capacitor with air between the plates has a capacitance of $12 \mu F$. If the distance between the plates is doubled and the space between the plates is filled with a substance of dielectric constant $4$,what will be the new capacitance of the capacitor (in $\mu F$)?

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