A parallelogram has sides 60, cm and 40, cm a | vedclass

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(D) The area of a triangle with sides $a, b, c$ is given by Heron's formula: $	ext{Area} = \sqrt{S(S-a)(S-b)(S-c)}$,where $S = \frac{a+b+c}{2}$.In $\

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$600 \sqrt{15}\, cm^2$

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(D) The area of a triangle with sides $a, b, c$ is given by Heron's formula: $	ext{Area} = \sqrt{S(S-a)(S-b)(S-c)}$,where $S = \frac{a+b+c}{2}$.In $\Delta ABC$,the sides are $a = 60\, cm$,$b = 40\, cm$,and $c = 80\, cm$.The semi-perimeter $S = \frac{60 + 40 + 80}{2} = \frac{180}{2} = 90\, cm$.Area of $\Delta ABC = \sqrt{90(90-60)(90-40)(90-80)}$$= \sqrt{90 	imes 30 	imes 50 	imes 10} = \sqrt{1350000} = \sqrt{90000 	imes 15} = 300 \sqrt{15}\, cm^2$.$A$ diagonal divides a parallelogram into two triangles of equal area.Therefore,the area of parallelogram $ABCD = 2 	imes 	ext{Area of } \Delta ABC$.Area $= 2 	imes 300 \sqrt{15} = 600 \sqrt{15}\, cm^2$.

$A$ parallelogram has sides $60\, cm$ and $40\, cm$ and one of its diagonals is $80\, cm$ long. Its area is

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