$A$ particle executes $SHM$ on a straight line path. The amplitude of oscillation is $2 \, cm$. When the displacement of the particle from the mean position is $1 \, cm$,the numerical value of the magnitude of acceleration is equal to the numerical value of the magnitude of velocity. The frequency of $SHM$ is (in $s^{-1}$):
- A$2\pi \sqrt{3}$
- B$\frac{2\pi}{\sqrt{3}}$
- C$\frac{\sqrt{3}}{2\pi}$
- D$\frac{1}{2\pi \sqrt{3}}$
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