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(B) Given that the particle starts from rest,initial velocity $u = 0$. Let the constant acceleration be $a$.For the first $10 \,s$ $(t_1 = 10 \,s)$:Us

Vedclass · Accepted Answer

${S_1} = {S_2}/3$

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(B) Given that the particle starts from rest,initial velocity $u = 0$. Let the constant acceleration be $a$.For the first $10 \,s$ $(t_1 = 10 \,s)$:Using the equation of motion $S = ut + \frac{1}{2}at^2$,we get:${S_1} = 0 	imes 10 + \frac{1}{2}a(10)^2 = 50a$ .....$(i)$To find the distance in the next $10 \,s$,we first find the velocity at $t = 10 \,s$:$v = u + at = 0 + a(10) = 10a$.For the next $10 \,s$ $(t_2 = 10 \,s)$,the initial velocity is $10a$:${S_2} = (10a)(10) + \frac{1}{2}a(10)^2$${S_2} = 100a + 50a = 150a$ .....(ii)Comparing equations $(i)$ and (ii):${S_1} = 50a$ and ${S_2} = 150a$Therefore,${S_2} = 3{S_1}$,which implies ${S_1} = {S_2}/3$.

$A$ particle experiences a constant acceleration for $20 \,s$ after starting from rest. If it travels a distance ${S_1}$ in the first $10 \,s$ and a distance ${S_2}$ in the next $10 \,s$,then:

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