$A$ particle is executing $S.H.M.$ Then the graph of acceleration as a function of displacement is

The displacement of a particle performing $S.H.M.$ is given by $x=5 \sin (3 t+3)$,where $x$ is in $cm$ and $t$ is in $s$. The maximum acceleration of the particle will be (in $cm \ s^{-2}$)

The displacement of a particle moving in $S.H.M.$ at any instant is given by $y = a \sin \omega t$. The acceleration after time $t = \frac{T}{4}$ is (where $T$ is the time period).

Where is maximum acceleration and zero acceleration of a particle executing $SHM$?

$A$ particle vibrating simple harmonically has an acceleration of $16 \ cm/s^2$ when it is at a distance of $4 \ cm$ from the mean position. Its time period is: (in $s$)

$A$ man of mass $M$ is standing on a platform. The platform is executing $S.H.M.$ of frequency $f$ in the vertical direction. The span of oscillation is $L$. What is the acceleration of the platform at the top of the oscillation?