$A$ particle is executing simple harmonic motion $(SHM)$ of amplitude $A$ along the $x$-axis about $x = 0$. When its potential energy $(PE)$ equals kinetic energy $(KE)$,the position of the particle will be
- A$\frac{A}{2}$
- B$\frac{A}{2\sqrt{2}}$
- C$\frac{A}{\sqrt{2}}$
- D$A$
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