$A$ particle is thrown with any velocity vertically upward. The distance travelled by the particle in the first second of its descent is:

$A$ stone is thrown with an initial speed of $4.9 \, m/s$ from a bridge in a vertically upward direction. It falls down into the water after $2 \, s$. The height of the bridge is .......... $m$.

$A$ horizontal bridge is built across a river. $A$ student standing on the bridge throws a small ball vertically upwards with a velocity $4\,m s^{-1}$. The ball strikes the water surface after $4\,s$. The height of the bridge above the water surface is $......\,m$ (Take $g=10\,m s^{-2}$).

$A$ juggler tosses a ball up in the air with initial speed $u$. At the instant it reaches its maximum height $H$,he tosses up a second ball with the same initial speed. The two balls will collide at a height:

Assertion: The zero velocity of a particle at any instant always implies zero acceleration at that instant.
Reason: $A$ body is momentarily at rest when it reverses its direction of motion.
The correct option among the following is:

$A$ ball is thrown vertically upwards with a velocity $u$. What is the distance covered by it in the last $t$ seconds of its upward motion?