A particle moves in a circular path with decr | vedclass

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Question

(D) The angular momentum $\vec L$ is defined as $\vec L = \vec r 	imes \vec p$. For a particle moving in a circular path,the position vector $\vec r$

Vedclass · Accepted Answer

The direction of angular momentum remains constant

Vedclass · Answer

(D) The angular momentum $\vec L$ is defined as $\vec L = \vec r 	imes \vec p$. For a particle moving in a circular path,the position vector $\vec r$ and linear momentum $\vec p$ lie in the plane of the circle. According to the right-hand rule,the direction of $\vec L$ is perpendicular to the plane of rotation. Since the particle continues to move in the same circular path,the plane of rotation does not change. Therefore,the direction of the angular momentum vector remains constant,even if its magnitude changes due to the decreasing speed of the particle. Thus,option $(D)$ is correct.

$A$ particle moves in a circular path with decreasing speed. Choose the correct statement.

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