A particle of charge q = -16 times 10^{-18} , | vedclass

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(B) The particle moves undeflected along the $x$-axis,which means the net Lorentz force acting on the particle is zero.The Lorentz force is given by $

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$10^3 \, Wb/m^2$

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(B) The particle moves undeflected along the $x$-axis,which means the net Lorentz force acting on the particle is zero.The Lorentz force is given by $\vec{F} = q(\vec{E} + \vec{v} 	imes \vec{B})$.For the particle to move undeflected,the electric force must be equal and opposite to the magnetic force: $q\vec{E} + q(\vec{v} 	imes \vec{B}) = 0$.Given $\vec{v} = v\hat{i}$,$\vec{B} = B\hat{j}$,and $\vec{E} = -E\hat{k}$.The magnetic force is $\vec{F}_m = q(v\hat{i} 	imes B\hat{j}) = qvB\hat{k}$.The electric force is $\vec{F}_e = q(-E\hat{k}) = -qE\hat{k}$.Equating the magnitudes: $qvB = qE$.Therefore,$B = E/v$.Substituting the given values: $B = \frac{10^4}{10} = 10^3 \, Wb/m^2$.

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