A particle of mass m strikes elastically on a | vedclass

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(A) In an elastic collision with a smooth wall,the component of velocity parallel to the wall remains unchanged.Let the velocity of the particle be $\

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(A) In an elastic collision with a smooth wall,the component of velocity parallel to the wall remains unchanged.Let the velocity of the particle be $\vec{v}$. The angle with the wall is $60^{\circ}$,so the angle with the normal to the wall is $90^{\circ} - 60^{\circ} = 30^{\circ}$.The component of velocity parallel to the wall is $v_{\parallel} = v \cos(60^{\circ})$.Since the wall is smooth,there is no impulsive force acting along the wall,meaning the parallel component of velocity remains constant throughout the collision.Initial momentum along the wall: $p_{i, \parallel} = m v \cos(60^{\circ})$.Final momentum along the wall: $p_{f, \parallel} = m v \cos(60^{\circ})$.Change in momentum along the wall: $\Delta p_{\parallel} = p_{f, \parallel} - p_{i, \parallel} = m v \cos(60^{\circ}) - m v \cos(60^{\circ}) = 0$.Therefore,the magnitude of the change in momentum along the wall is $0$.

Column-$I$	Column-$II$
$(1)$ Change in momentum	$(a)$ Force
$(2)$ Rate of change of momentum	$(b)$ Impulse

$A$ particle of mass $m$ strikes elastically on a wall with velocity $v$,at an angle of $60^{\circ}$ from the wall. The magnitude of the change in momentum of the particle along the wall is:

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