A particle of mass 10 , g is describing S.H.M | vedclass

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(C) The kinetic energy $K$ of a particle performing $S.H.M.$ is given by the formula: $K = \frac{1}{2} m \omega^2 (a^2 - y^2)$.Given: mass $m = 10 \,

Vedclass · Accepted Answer

$375 \pi^2 \, ergs$

Vedclass · Answer

(C) The kinetic energy $K$ of a particle performing $S.H.M.$ is given by the formula: $K = \frac{1}{2} m \omega^2 (a^2 - y^2)$.Given: mass $m = 10 \, g$,period $T = 2 \, s$,amplitude $a = 10 \, cm$,and displacement $y = 5 \, cm$.The angular frequency $\omega = \frac{2\pi}{T} = \frac{2\pi}{2} = \pi \, rad/s$.Substituting the values into the formula:$K = \frac{1}{2} 	imes 10 	imes (\pi)^2 	imes (10^2 - 5^2)$$K = 5 	imes \pi^2 	imes (100 - 25)$$K = 5 	imes \pi^2 	imes 75$$K = 375 \pi^2 \, ergs$.

$A$ particle of mass $10 \, g$ is describing $S.H.M.$ along a straight line with a period of $2 \, s$ and an amplitude of $10 \, cm$. Its kinetic energy when it is at $5 \, cm$ from its equilibrium position is

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