A particle starts from origin O from rest and | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Given that the particle starts from rest,the initial velocity $u = 0$.Since the particle moves with uniform acceleration,the acceleration $a$ is c

Vedclass · Accepted Answer

$a, b, d$

Vedclass · Answer

(D) Given that the particle starts from rest,the initial velocity $u = 0$.Since the particle moves with uniform acceleration,the acceleration $a$ is constant over time.$1$. For acceleration-time graph: Since $a$ is constant,the graph $(a)$ is a horizontal line parallel to the $t$-axis,which is correct.$2$. For velocity-time graph: Using the equation $v = u + at$,we get $v = 0 + at = at$. This represents a straight line passing through the origin,so graph $(b)$ is correct.$3$. For displacement-time graph: Using the equation $x = ut + \frac{1}{2}at^2$,we get $x = 0(t) + \frac{1}{2}at^2 = \frac{1}{2}at^2$. This represents a parabola opening upwards starting from the origin,so graph $(d)$ is correct.Therefore,the figures $(a)$,$(b)$,and $(d)$ correctly represent the motion.

$A$ particle starts from origin $O$ from rest and moves with a uniform acceleration along the positive $x$-axis. Identify all figures that correctly represent the motion qualitatively. ($a =$ acceleration,$v =$ velocity,$x =$ displacement,$t =$ time)

Similar Questions

The stopping distance of a vehicle moving with a given acceleration is proportional to the ....... of its speed.

$A$ body starts from rest and moves with a uniform acceleration. The ratio of the distance covered by the body in the $n^{\text{th}}$ second of its motion to the total distance travelled in $n$ seconds is

$A$ car passes three points $A$, $B$ and $C$ at $3 \text{ m/s}$, $6 \text{ m/s}$ and $9 \text{ m/s}$ respectively in a straight line with uniform acceleration. If distance $AB = 60 \text{ m}$, then find the distance $BC$. (in $m$)

The relation between time $t$ and distance $x$ is given by $t = \alpha x^2 + \beta x$,where $\alpha$ and $\beta$ are constants. If $v$ is the velocity,then what is the retardation?

Tripling the speed of the motor car multiplies the distance needed for stopping it by

Vedclass Test Series

Exam Paper Generator

Online Exam Module