A particle with charge -Q and mass m enters a | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) When a charged particle enters a uniform magnetic field perpendicular to its velocity, it follows a circular path.
From the geometry of the path

Vedclass · Accepted Answer

$T \left( \frac{\pi - 2	heta}{2\pi} ight)$

Vedclass · Answer

(D) When a charged particle enters a uniform magnetic field perpendicular to its velocity, it follows a circular path.
From the geometry of the path shown in the figure, the angle $\alpha$ subtended by the arc of the path inside the magnetic field at the center $C$ is related to the angle $	heta$ by the relation $\alpha + 	heta + 	heta = \pi$, which gives $\alpha = \pi - 2	heta$.
The time period of a full circular orbit is $T = \frac{2\pi m}{QB}$.
The time $t$ spent by the particle in the magnetic field is proportional to the angle $\alpha$ subtended at the center:
$t = \frac{\alpha}{2\pi} T$
Substituting $\alpha = \pi - 2	heta$, we get:
$t = \frac{\pi - 2	heta}{2\pi} T = T \left( \frac{\pi - 2	heta}{2\pi} ight)$.

$A$ particle with charge $-Q$ and mass $m$ enters a magnetic field of magnitude $B$, which exists only to the of the boundary $YZ$. The direction of the motion of the particle is perpendicular to the direction of $B$. Let $T = 2\pi \frac{m}{QB}$. The time spent by the particle in the field will be:

Similar Questions

$A$ particle of mass $0.6 \,g$ and having charge of $25 \,nC$ is moving horizontally with a uniform velocity $1.2 \times 10^4 \,ms^{-1}$ in a uniform magnetic field. The value of the magnetic induction is $\left(g=10 \,ms^{-2}\right)$.

An electron,moving in a uniform magnetic field of induction of intensity $\vec{B}$,has its radius directly proportional to

$A$ charge $Q$ moves parallel to a very long straight wire carrying a current $I$ as shown. The force on the charge is

Which of the following particles will describe the smallest circle when projected with the same velocity perpendicular to the magnetic field?

Vedclass Test Series

Exam Paper Generator

Online Exam Module