A person in a lift is holding a water jar,whi | vedclass

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Question

(A) The horizontal range $d$ of a water jet from a hole at height $h_2$ from the bottom,with $h_1$ being the height of water above the hole,is given b

Vedclass · Accepted Answer

$P-2, Q-3, R-1, S-4$

Vedclass · Answer

(A) The horizontal range $d$ of a water jet from a hole at height $h_2$ from the bottom,with $h_1$ being the height of water above the hole,is given by $d = v \cdot t = \sqrt{2gh_1} \cdot \sqrt{\frac{2h_2}{g}} = 2\sqrt{h_1 h_2}$.Here,$g$ is the effective acceleration due to gravity $(g_{eff})$ inside the lift.$P$. When the lift accelerates vertically up,$g_{eff} = g + a > g$. Since $d \propto \frac{1}{\sqrt{g_{eff}}}$,$d$ decreases. Thus,$d $Q$. When the lift accelerates vertically down with $a  1.2 \ m$.$R$. When the lift moves with constant speed,$a = 0$,so $g_{eff} = g$. Thus,$d = 1.2 \ m$.$S$. When the lift is falling freely,$a = g$,so $g_{eff} = g - g = 0$. Since there is no effective gravity,the pressure at the hole is zero,and no water leaks out.Matching: $P-2, Q-3, R-1, S-4$.

List-$I$	List-$II$
$P$. Lift is accelerating vertically up.	$1$. $d = 1.2 \ m$
$Q$. Lift is accelerating vertically down with an acceleration less than the gravitational acceleration.	$2$. $d < 1.2 \ m$
$R$. Lift is moving vertically up with constant speed.	$3$. $d > 1.2 \ m$
$S$. Lift is falling freely.	$4$. No water leaks out of the jar.

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