$A$ person standing on a rotating platform has his hands lowered. He suddenly outstretch his arms. The angular momentum

When a person dancing on ice pulls their arms inward,they start spinning faster. This is due to:

If the radius of a rotating disc is suddenly halved while its mass remains the same,its angular velocity will become:

When a dancer pulls their arms inward while spinning on ice,they spin faster. This is due to:

$A$ thin rod of mass $0.9\, kg$ and length $1\, m$ is suspended,at rest,from one end so that it can freely oscillate in the vertical plane. $A$ particle of mass $0.1\, kg$ moving in a straight line with velocity $80\, m/s$ hits the rod at its bottom-most point and sticks to it. The angular speed (in $rad/s$) of the rod immediately after the collision will be

$A$ circular disc of mass $M$ has an initial angular velocity $\omega_1$. Two small spheres,each of mass $m$,are attached to the disc at opposite points on its diameter. What will be the final angular velocity of the disc?