A person who can see things most clearly at a | vedclass

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Question

(A) The person suffers from myopia (nearsightedness) and needs to see an object placed at $u = -30 \, cm$ as if it were at their near point of $v = -1

Vedclass · Accepted Answer

$15 \, cm$ (Concave)

Vedclass · Answer

(A) The person suffers from myopia (nearsightedness) and needs to see an object placed at $u = -30 \, cm$ as if it were at their near point of $v = -10 \, cm$. Using the lens formula: $\frac{1}{f} = \frac{1}{v} - \frac{1}{u}$. Substituting the values: $\frac{1}{f} = \frac{1}{-10} - \frac{1}{-30}$. $\frac{1}{f} = -\frac{1}{10} + \frac{1}{30} = \frac{-3 + 1}{30} = \frac{-2}{30} = -\frac{1}{15}$. Therefore,$f = -15 \, cm$. The negative sign indicates a concave lens with a focal length of $15 \, cm$.

$A$ person who can see things most clearly at a distance of $10 \, cm$ requires spectacles to enable him to see clearly things at a distance of $30 \, cm$. What should be the focal length of the spectacles?

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