A person's present age is two-fifth of the ag | vedclass

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(C) Let the mother's present age be $M$ years.The person's present age is $\frac{2}{5}M$.After $8$ years,the mother's age will be $M + 8$ and the pers

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$40$

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(C) Let the mother's present age be $M$ years.The person's present age is $\frac{2}{5}M$.After $8$ years,the mother's age will be $M + 8$ and the person's age will be $\frac{2}{5}M + 8$.According to the problem,after $8$ years,the person's age will be one-half of the mother's age:$\frac{2}{5}M + 8 = \frac{1}{2}(M + 8)$Multiply both sides by $10$ to clear the fractions:$4M + 80 = 5(M + 8)$$4M + 80 = 5M + 40$Rearranging the terms to solve for $M$:$80 - 40 = 5M - 4M$$M = 40$Therefore,the mother's present age is $40$ years.

$A$ person's present age is two-fifth of the age of his mother. After $8$ years,he will be one-half of the age of his mother. How old is the mother at present (in $years$)?

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