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(C) The intensity $I$ of light from a point source follows the inverse square law,$I \propto \frac{1}{d^2}$.Since the number of photoelectrons emitted

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Number of electrons emitted is a quarter of the initial number

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(C) The intensity $I$ of light from a point source follows the inverse square law,$I \propto \frac{1}{d^2}$.Since the number of photoelectrons emitted per second is directly proportional to the intensity of incident light,we have $n \propto I \propto \frac{1}{d^2}$.Given initial distance $d_1 = 1\;m$ and final distance $d_2 = 2\;m$.Therefore,the ratio of the number of electrons is $\frac{n_2}{n_1} = \left( \frac{d_1}{d_2} \right)^2 = \left( \frac{1}{2} \right)^2 = \frac{1}{4}$.Thus,$n_2 = \frac{n_1}{4}$.The energy of each emitted electron depends on the frequency of the incident light,not on the intensity,so the energy remains unchanged.

$A$ photoelectric cell is illuminated by a point source of light $1\;m$ away. When the source is shifted to $2\;m$,then:

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