A plane pi makes intercepts 3 and 4 respectiv | vedclass

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(A) The intercept form of a plane is given by $\frac{x}{a} + \frac{y}{b} + \frac{z}{c} = 1$.Given that the plane is parallel to the $y$-axis,the $y$-i

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$3x + 4z = 12$

Vedclass · Answer

(A) The intercept form of a plane is given by $\frac{x}{a} + \frac{y}{b} + \frac{z}{c} = 1$.Given that the plane is parallel to the $y$-axis,the $y$-intercept is infinite,which means the term involving $y$ is absent.The $x$-intercept is $a = 4$ and the $z$-intercept is $c = 3$.Substituting these values into the equation,we get $\frac{x}{4} + \frac{z}{3} = 1$.Multiplying the entire equation by $12$,we obtain $3x + 4z = 12$.

$A$ plane $\pi$ makes intercepts $3$ and $4$ respectively on the $z$-axis and $x$-axis. If $\pi$ is parallel to the $y$-axis,then its equation is:

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