A plane electromagnetic wave of frequency 500 | vedclass

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Question

(A) The relationship between the electric field $\overrightarrow{E}$ and the magnetic field $\overrightarrow{B}$ in an electromagnetic wave is given b

Vedclass · Accepted Answer

$-24 \hat{x}\, V/m$

Vedclass · Answer

(A) The relationship between the electric field $\overrightarrow{E}$ and the magnetic field $\overrightarrow{B}$ in an electromagnetic wave is given by $\overrightarrow{E} = c(\overrightarrow{B} 	imes \hat{n})$,where $\hat{n}$ is the direction of propagation.Given,the wave travels along the $y$-direction,so $\hat{n} = \hat{y}$.The magnetic field is $\overrightarrow{B} = 8.0 	imes 10^{-8} \hat{z}\, T$.Substituting the values:$\overrightarrow{E} = (3 	imes 10^{8}\, m/s) 	imes (8.0 	imes 10^{-8} \hat{z} 	imes \hat{y})$Since $\hat{z} 	imes \hat{y} = -\hat{x}$,we get:$\overrightarrow{E} = (3 	imes 8.0) 	imes (-\hat{x}) = -24 \hat{x}\, V/m$.

Similar Questions

$A$ point source of electromagnetic radiation has an average power output of $800\,W$. The maximum value of the electric field at a distance of $3.5\,m$ from the source will be.....$V/m$.

Which of the following statements is false regarding the properties of electromagnetic waves?

In an $EM$ wave,the amplitude of the magnetic field $H_0$ and the amplitude of the electric field $E_0$ at any place are related as:

If the magnetic field of a plane electromagnetic wave is given by (The speed of light $c = 3 \times 10^8 \, m/s$):
$B = 100 \times 10^{-6} \sin \left[ 2\pi \times 2 \times 10^{15} \left( t - \frac{x}{c} \right) \right]$
Then the maximum electric field associated with it is:

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