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(A) $1$. Inside a hollow conducting sphere,the electric field lines must terminate perpendicular to the inner surface of the conductor because the sur

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(A) $1$. Inside a hollow conducting sphere,the electric field lines must terminate perpendicular to the inner surface of the conductor because the surface of a conductor is an equipotential surface.$2$. Since the charge $q$ is not at the center,the field lines will not be radially symmetric inside the cavity; they will be denser on the side closer to the charge.$3$. There can be no electric field lines within the material of the conducting shell itself,as the electric field inside a conductor in electrostatic equilibrium is zero.$4$. Outside the shell,the electric field lines appear as if they originate from a point charge located at the center of the sphere,due to the induced charge distribution on the outer surface of the shell.$5$. Based on these principles,the pattern shown in option $A$ correctly depicts the lines terminating perpendicularly on the inner surface and the radially symmetric field outside the shell.

$A$ point charge $q$ is placed at a point inside a hollow conducting sphere. Which of the following electric force patterns is correct?

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