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Question

(A) According to Gauss's Law,the total electric flux $\phi$ through any closed surface is equal to the net charge $q_{enc}$ enclosed by the surface di

Vedclass · Accepted Answer

$\frac{q}{\varepsilon_0}$

Vedclass · Answer

(A) According to Gauss's Law,the total electric flux $\phi$ through any closed surface is equal to the net charge $q_{enc}$ enclosed by the surface divided by the permittivity of free space $\varepsilon_0$.Mathematically,$\phi = \frac{q_{enc}}{\varepsilon_0}$.In this problem,the point charge $+q$ is enclosed by the cube.Therefore,the total electric flux emerging from the cube is $\phi = \frac{q}{\varepsilon_0}$.

$A$ point charge $+q$ is placed at the centre of a cube of side $L$. The electric flux emerging from the cube is

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