A point charge +Q is positioned at the centre | vedclass

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(C) According to Gauss's Law,the total flux through a closed surface is $\frac{q_{enclosed}}{\varepsilon_0}$.Since the charge $+Q$ is placed at the ce

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$\frac{Q}{8\varepsilon_0}$

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(C) According to Gauss's Law,the total flux through a closed surface is $\frac{q_{enclosed}}{\varepsilon_0}$.Since the charge $+Q$ is placed at the center of the base,it lies on the boundary of the pyramid. To enclose the charge completely,we can place an identical pyramid on top of the base,forming a closed structure (like an octahedron).The total flux through this closed structure is $\frac{Q}{\varepsilon_0}$.By symmetry,the flux through the original pyramid is half of the total flux,which is $\frac{Q}{2\varepsilon_0}$.This flux is distributed equally among the $4$ identical triangular faces of the pyramid.Therefore,the flux through one face is $\frac{1}{4} 	imes \frac{Q}{2\varepsilon_0} = \frac{Q}{8\varepsilon_0}$.

$A$ point charge $+Q$ is positioned at the centre of the base of a square pyramid as shown. The flux through one of the four identical upper faces of the pyramid is

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