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(C) Let the position of the object be $x_O$ and the position of the mirror be $x_M$. The position of the image $x_I$ is given by the relation $x_I - x

Vedclass · Accepted Answer

$4$

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(C) Let the position of the object be $x_O$ and the position of the mirror be $x_M$. The position of the image $x_I$ is given by the relation $x_I - x_M = -(x_O - x_M)$,which simplifies to $x_I = 2x_M - x_O$.Since the object is stationary,$x_O$ is constant,so $v_O = 0$.Differentiating with respect to time,we get the velocity of the image: $v_I = 2v_M - v_O = 2v_M$.Integrating or considering the displacement,the amplitude of the image $A_I$ is related to the amplitude of the mirror $A_M$ by $A_I = 2A_M$.Given $A_M = 2 \ cm$,the amplitude of the image is $A_I = 2 	imes 2 \ cm = 4 \ cm$.

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