A polaroid is placed at 45^{circ} to an incom | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) According to Malus's Law,the intensity of polarized light passing through an analyzer is given by $I = I_{max} \cos^2 	heta$,where $	heta$ is th

Vedclass · Accepted Answer

$I_0/2$

Vedclass · Answer

(B) According to Malus's Law,the intensity of polarized light passing through an analyzer is given by $I = I_{max} \cos^2 	heta$,where $	heta$ is the angle between the transmission axis of the polarizer and the analyzer.However,for unpolarized light passing through a single polaroid,the intensity is reduced by half regardless of the orientation,provided the light is unpolarized.If the incoming light is already polarized,we use Malus's Law: $I = I_0 \cos^2 	heta$.Given $	heta = 45^{\circ}$:$I = I_0 \cos^2(45^{\circ})$$I = I_0 	imes (1/\sqrt{2})^2$$I = I_0 	imes (1/2)$$I = I_0/2$

$A$ polaroid is placed at $45^{\circ}$ to an incoming light of intensity $I_0$. Now,the intensity of light passing through the polaroid after polarization would be:

Similar Questions

Name the method of asexual reproduction in lichens.

Fusion reaction is initiated with the help of

Given that $a, b \in \{0, 1, 2, \ldots, 9\}$ with $a+b \neq 0$ and that $\left(a+\frac{b}{10}\right)^x = \left(\frac{a}{10}+\frac{b}{100}\right)^y = 1000$. Then,$\frac{1}{x}-\frac{1}{y}$ is equal to

If $\operatorname{cosec} \theta = \frac{p+q}{p-q}$,then $\cot \left(\frac{\pi}{4} + \frac{\theta}{2}\right)$ is equal to

Methanogens belong to:

Vedclass Test Series

Exam Paper Generator

Online Exam Module