A polyatomic gas left( gamma = frac{4}{3} rig | vedclass

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(B) For an adiabatic process,the relationship between pressure and volume is given by $P_1 V_1^\gamma = P_2 V_2^\gamma$.Given: Initial pressure $P_1 =

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$16$

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(B) For an adiabatic process,the relationship between pressure and volume is given by $P_1 V_1^\gamma = P_2 V_2^\gamma$.Given: Initial pressure $P_1 = P_0$,initial volume $V_1 = V$,final volume $V_2 = \frac{V}{8}$,and adiabatic index $\gamma = \frac{4}{3}$.Substituting these values into the equation:$P_2 = P_1 \left( \frac{V_1}{V_2} \right)^\gamma$$P_2 = P_0 \left( \frac{V}{V/8} \right)^{4/3}$$P_2 = P_0 (8)^{4/3}$$P_2 = P_0 (2^3)^{4/3}$$P_2 = P_0 (2)^4$$P_2 = 16P_0$.

$A$ polyatomic gas $\left( \gamma = \frac{4}{3} \right)$ is compressed to $\frac{1}{8}$ of its volume adiabatically. If its initial pressure is $P_0$,its new pressure will be (in $P_0$)

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