$A$ prism of refractive index $\mu$ and angle $A$ is placed in the minimum deviation position. If the angle of minimum deviation is $A,$ then the value of $A$ in terms of $\mu$ is

The glass prisms $P_{1}$ and $P_{2}$ are to be combined together to produce dispersion without deviation. The angles of the prisms $P_{1}$ and $P_{2}$ are selected as $4^{\circ}$ and $3^{\circ}$ respectively. If the refractive index of prism $P_{1}$ is $1.54,$ then that of $P_{2}$ will be

$A$ thin prism $P_{1}$ with angle $4^{\circ}$ and made from glass of refractive index $1.54$ is combined with another thin prism $P_{2}$ made from glass of refractive index $1.72$ to produce dispersion without deviation. The angle of prism for $P_{2}$ is (in $^{\circ}$)

The refracting angle of a glass prism is $30^{\circ}$. $A$ ray is incident on one of the faces and is perpendicular to it. The angle of deviation $\delta$ between the incident ray and the ray that leaves the prism is (Refractive index of glass $= 1.5$) (Given: $\sin(30^{\circ}) = 0.5, \sin(48.6^{\circ}) = 0.75$). (in $^{\circ}$)

The refractive index of a prism with apex angle $A$ is $\cot(A/2)$. The angle of minimum deviation is:

The angle of the prism is $30^o$. The rays incident at an angle of $60^o$ at one refracting face suffer a deviation of $30^o$. Then the angle of emergence is......$^o$