A protein 'A' contains 0.30, % of glycine (mo | vedclass

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(A) The minimum molar mass of a protein is calculated assuming that at least one molecule of the constituent (glycine) is present in the protein molec

Vedclass · Accepted Answer

$25$

Vedclass · Answer

(A) The minimum molar mass of a protein is calculated assuming that at least one molecule of the constituent (glycine) is present in the protein molecule.Given that $0.30\, \%$ of the protein is glycine,we have:$0.30\, g$ of glycine in $100\, g$ of protein.Since the molecular weight of glycine is $75\, g\, mol^{-1}$,the minimum molar mass of the protein is calculated as:$	ext{Minimum molar mass} = \frac{	ext{Molecular weight of glycine} 	imes 100}{	ext{Percentage of glycine}}$$	ext{Minimum molar mass} = \frac{75 	imes 100}{0.30} = \frac{7500}{0.30} = 25000\, g\, mol^{-1}$Converting this to the required format: $25000\, g\, mol^{-1} = 25 	imes 10^{3} \, g\, mol^{-1}$.Thus,the value is $25$.

$A$ protein $'A'$ contains $0.30\, \%$ of glycine (molecular weight $75$). The minimum molar mass of the protein $'A'$ is $.......\, \times 10^{3} \, g\, mol^{-1}$ [nearest integer]

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