A question paper has 2 parts,part A and part | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The number of ways to choose $8$ questions from $10$ in part $A$ is given by $C(10, 8)$.The number of ways to choose $5$ questions from $10$ in pa

Vedclass · Accepted Answer

$11340$

Vedclass · Answer

(D) The number of ways to choose $8$ questions from $10$ in part $A$ is given by $C(10, 8)$.The number of ways to choose $5$ questions from $10$ in part $B$ is given by $C(10, 5)$.Since these are independent selections,the total number of ways is the product of the two combinations:Total ways $= C(10, 8) 	imes C(10, 5)$$= \frac{10!}{8!2!} 	imes \frac{10!}{5!5!}$$= \frac{10 	imes 9}{2 	imes 1} 	imes \frac{10 	imes 9 	imes 8 	imes 7 	imes 6}{5 	imes 4 	imes 3 	imes 2 	imes 1}$$= 45 	imes 252 = 11340$.

$A$ question paper has $2$ parts,part $A$ and part $B$,each containing $10$ questions. If a student has to choose $8$ questions from part $A$ and $5$ questions from part $B$,in how many ways can the student choose the questions?

Similar Questions

There are $6$ men and $8$ women in a club. $A$ committee of $5$ people has to be formed. What will be the number of ways to select $5$ people if at least one woman is selected?

If $n$ and $r$ are two positive integers such that $n \ge r,$ then $^nC_{r-1} + ^nC_r = $

How many numbers greater than $100$ and divisible by $5$ can be made from the digits $3, 4, 5, 6$,if no digit is repeated?

In how many ways can $12$ gentlemen sit around a round table so that three specified gentlemen are always together?

How many $3$-digit numbers can be formed by using the digits $0, 2, 3, 6, 8$ when the digits may be repeated any number of times?

Vedclass Test Series

Exam Paper Generator

Online Exam Module