$A$ radiowave has a maximum electric field intensity of $10^{-4} \, V/m$ on arrival at a receiving antenna. The maximum magnetic flux density of such a wave is:

The oscillating electric field of an electromagnetic wave is given by $E_y = 30 \sin(2 \times 10^{11} t + 300 \pi x) \ Vm^{-1}$. Then,the value of the wavelength of the electromagnetic wave is

For electromagnetic waves,the phase difference between the $\vec{E}$ and $\vec{B}$ vectors (for the region far from the source) is......

The electric field of a plane electromagnetic wave, travelling in an unknown non-magnetic medium is given by, $E_y = 20 \sin(3 \times 10^6 x - 4.5 \times 10^{14} t) \text{ V/m}$ (where $x, t$ and other values are in $S$.$I$. units). The dielectric constant of the medium is . . . . . . . (Speed of light in free space is $c = 3 \times 10^8 \text{ m/s}$)

The ratio of the amplitude of the magnetic field to the amplitude of the electric field for an electromagnetic wave propagating in vacuum is equal to:

The velocity factor of a transmission line is $x$. If the dielectric constant of the medium is $2.6$,the value of $x$ is: