A reaction,A + B rightarrow C + D + q,is foun | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) For a reaction to be spontaneous,the Gibbs free energy change $\Delta G$ must be negative.The relationship is given by $\Delta G = \Delta H - T\De

Vedclass · Accepted Answer

possible at any temperature

Vedclass · Answer

(D) For a reaction to be spontaneous,the Gibbs free energy change $\Delta G$ must be negative.The relationship is given by $\Delta G = \Delta H - T\Delta S$.According to the reaction $A + B \rightarrow C + D + q$,the term $q$ indicates that heat is evolved,so the enthalpy change $\Delta H$ is negative.Given that the entropy change $\Delta S$ is positive,the term $-T\Delta S$ will always be negative for any temperature $T > 0$.Since both $\Delta H$ and $-T\Delta S$ are negative,$\Delta G$ will be negative at all temperatures.Therefore,the reaction is spontaneous at any temperature.

$A$ reaction,$A + B \rightarrow C + D + q$,is found to have a positive entropy change. The reaction will be:

Similar Questions

For a spontaneous process,which of the following conditions is most favorable?

Which of the following reactions is expected to never be spontaneous?

One mole of an ideal gas at $1 \ atm$ pressure is filled in a bulb of $10 \ L$ capacity and is connected to a vacuum bulb of $100 \ L$ capacity. How much work is done in this process in Joules?

For a reaction with $\Delta H = +ve$ and $\Delta S = +ve$,which of the following statements is correct?

Calculate the work done if $1 \ mole$ of an ideal gas is compressed isothermally and reversibly from $12 \ dm^3$ to $6 \ dm^3$ at $300 \ K$. $\left[R = 8.314 \ J \ K^{-1} \ mol^{-1}\right]$ (in $kJ$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module