$A$ reaction attains equilibrium when the free energy change accompanying it is

For the reaction $CH_{4(g)} + H_{2(g)} \longrightarrow C_2H_{6(g)}$,$K_p = 3.356 \times 10^{17}$,calculate $\Delta G^{\circ}$ for the reaction at $298 \ K$.

When a reaction is carried out at standard states,then at equilibrium:

For a system in equilibrium,$\Delta G = 0$ under conditions of constant:

Explain chemical equilibrium and free Gibbs energy change by $\Delta G$.

The $INCORRECT$ match in the following is