$A$ reaction between a proton and $_8^{18}O$ that produces $_9^{18}F$ must also liberate:

Nuclear forces are

Obtain approximately the ratio of the nuclear radii of the gold isotope $^{197}_{79}Au$ and the silver isotope $^{107}_{47}Ag$.

Assertion $(A):$ Forces acting between proton-proton $(f_{pp})$, proton-neutron $(f_{pn})$ and neutron-neutron $(f_{nn})$ are such that $f_{pp} < f_{pn} = f_{nn}$.
Reason $(R):$ Electrostatic force of repulsion between two protons reduces the net nuclear force between them.

Two protons are kept at a separation of $40 \text{ Å}$. $F_{n}$ is the nuclear force and $F_{e}$ is the electrostatic force between them. Then:

The radius of germanium $(Ge)$ nuclide is measured to be twice the radius of ${ }_4^9 Be$. The number of nucleons in $Ge$ will be