$A$ rectangular loop has a sliding connector $PQ$ of length $l$ and resistance $R \, \Omega$. It is moving with a speed $v$ as shown. The setup is placed in a uniform magnetic field directed into the plane of the paper. The three currents $I_1$, $I_2$, and $I$ are:

  • A
    $I_1 = I_2 = \frac{Blv}{6R}, \, I = \frac{Blv}{3R}$
  • B
    $I_1 = -I_2 = \frac{Blv}{R}, \, I = \frac{2Blv}{R}$
  • C
    $I_1 = I_2 = \frac{Blv}{3R}, \, I = \frac{2Blv}{3R}$
  • D
    $I_1 = I_2 = I = \frac{Blv}{R}$

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