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(C) The dimensions of the rectangular parallelopiped are $1\,cm 	imes 1\,cm 	imes 100\,cm$. The current flows between the two opposite rectangular f

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$3$

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(C) The dimensions of the rectangular parallelopiped are $1\,cm 	imes 1\,cm 	imes 100\,cm$. The current flows between the two opposite rectangular faces of size $1\,cm 	imes 100\,cm$. Thus,the length of the path of the current is $\ell = 1\,cm = 10^{-2}\,m$. The area of the cross-section through which the current flows is $A = 1\,cm 	imes 100\,cm = 10^{-2}\,m 	imes 1\,m = 10^{-2}\,m^2$. The specific resistance (resistivity) is $ho = 3 	imes 10^{-7}\,\Omega\,m$. The resistance $R$ is given by the formula $R = ho \frac{\ell}{A}$. Substituting the values: $R = (3 	imes 10^{-7}) 	imes \frac{10^{-2}}{10^{-2}} = 3 	imes 10^{-7}\,\Omega$. Therefore,the resistance is $3 	imes 10^{-7}\,\Omega$.

$A$ rectangular parallelopiped is measured as $1\,cm \times 1\,cm \times 100\,cm$. If its specific resistance is $3 \times 10^{-7}\,\Omega\,m$,then the resistance between its two opposite rectangular faces (as shown in the figure) will be $.......... \times 10^{-7} \Omega$.

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