A road is banked at an angle of 30^o to the h | vedclass

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(C) The condition for a car to experience no friction on a banked road is given by the formula: $	an 	heta = \frac{v^2}{rg}$.Given: $	heta = 30^o$,

Vedclass · Accepted Answer

$36$

Vedclass · Answer

(C) The condition for a car to experience no friction on a banked road is given by the formula: $	an 	heta = \frac{v^2}{rg}$.Given: $	heta = 30^o$,$r = 10\sqrt{3} \ m$,and taking $g = 10 \ m/s^2$.Substituting the values: $	an 30^o = \frac{v^2}{(10\sqrt{3})(10)}$.Since $	an 30^o = \frac{1}{\sqrt{3}}$,we have: $\frac{1}{\sqrt{3}} = \frac{v^2}{100\sqrt{3}}$.Solving for $v^2$: $v^2 = \frac{100\sqrt{3}}{\sqrt{3}} = 100$.Thus,$v = 10 \ m/s$.To convert the velocity into $km/hr$,multiply by $\frac{18}{5}$: $v = 10 	imes \frac{18}{5} = 36 \ km/hr$.

$A$ road is banked at an angle of $30^o$ to the horizontal for negotiating a curve of radius $10\sqrt{3} \ m$. At what velocity will a car experience no friction while negotiating the curve? ............... $km/hr$

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