A rocket with a lift-off mass 2 times 10^4,kg | vedclass

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(B) Given: Mass of the rocket $m = 2 	imes 10^4\,kg$.Initial acceleration $a = 5\,m\,s^{-2}$.Acceleration due to gravity $g = 10\,m\,s^{-2}$.The rock

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$3 	imes 10^5\,N$

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(B) Given: Mass of the rocket $m = 2 	imes 10^4\,kg$.Initial acceleration $a = 5\,m\,s^{-2}$.Acceleration due to gravity $g = 10\,m\,s^{-2}$.The rocket is moving upwards,so the net force $F_{net}$ acting on the rocket is given by Newton's second law: $F_{net} = ma$.The forces acting on the rocket are the upward thrust $T$ and the downward gravitational force $mg$.Therefore,the equation of motion is: $T - mg = ma$.Rearranging for thrust $T$: $T = m(a + g)$.Substituting the values: $T = (2 	imes 10^4\,kg) 	imes (5\,m\,s^{-2} + 10\,m\,s^{-2})$.$T = (2 	imes 10^4) 	imes (15) = 30 	imes 10^4\,N$.$T = 3 	imes 10^5\,N$.

$A$ rocket with a lift-off mass $2 \times 10^4\,kg$ is blasted upwards with an initial acceleration of $5\,m\,s^{-2}$. The initial thrust of the blast is (Take $g = 10\,m\,s^{-2}$).

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