$A$ runs $1 \frac{3}{8}$ times as fast as $B$. If $A$ gives $B$ a start of $120 \, m$ and they reach the goal at the same time,the goal is at a distance of (in $m$)

  • A
    $360$
  • B
    $440$
  • C
    $460$
  • D
    $380$

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